pi
x0 = 100 # initial amount p = 5 # interest rate N = 4 # number of years nx=[[i,0] for i in range(N+1)] # solution: nx[0][1] = x0 for n in range(1,N+1): nx[n][1] = nx[n-1][1] + (p/100.0)*nx[n-1][1] show(nx) gra=line(nx) show(gra)
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